It does not depend on the amplitude of oscillation. Time taken to complete half oscillation, i.e. The mean, median, and mode are known as the measures of central tendency. of divisions on the circular head = (1/100) mm = 0.01 mm or 0.001 cm, (ii) Main scale reading = 2mm = 0.2 cm No. Usually in math, we encounter a few expression where they place two sets of two terms, both in brackets side by side like this (a+b)(a-b).This requiring removing of brackets and... Factorisation or factoring is the decomposition of an object (for example, a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original. Let the new time period be T’ and let g’ be the acceleration due to gravity. How is it considered to get the correct measurement? It will help them to memorize the process for the long run. Ratchet helps to advance the screw by turning it until the object is gently held between the stud and spindle of the screw. 1 min = 60 s 1 yr = 3.1536 × 107 s. A leap year is the year in which the month of February has 29 days. (b) If the acceleration due to gravity is reduced to one-fourth, Therefore, the time period is doubled. Two simple pendulums A and B have lengths 1.0 m and 4.0 m, respectively, at a certain place. (iv)Time period: This is the time taken to complete one oscillation. If speed of light is taken to be 3 × 108 m/s, find the distance from the sun to the earth in km. How do you determine it? of divisions on the circular scale = 50 (i) Pitch = Distance moved ahead in one revolution = 1 mm/1 = 1 mm. How can this accuracy be increased? of divisions on vernier callipers). of division of circular head in line with the base line (p) = 45 Circular scale reading = (p) × L.C. there are 100 divisions one the circular scale of a screw gauge. Let T1 and T2 be the time periods of the two pendulums of lengths l1 and l2, respectively. To get correct measurement with vernier callipers having a zero error, the zero error with its proper sign is always subtracted from the observed reading. (ii) L.C. What will be its new time period? (ii) Amplitude: The maximum displacement of the bob from its mean position on either side is called the amplitude of oscillation. Now, ab + length of p divisions on vernier scale = length of p divisions on main scale Alternatively, ab = length of p divisions on the main scale – length of p divisions on the vernier scale. Students can view or download the ICSE Sample Question Papers 2020 Solved Class 9 for their upcoming examination. This gives a to and fro motion about the mean position to the pendulum. The thickness of the wire could be determined from the reading as shown in the figure below. Selina Publishers Concise Physics for Class 9 ICSE Solutions all questions are solved and explained by expert teachers as per ICSE board guidelines. The two equations y... Any point on the coordinate axes can be denoted by a pair of numbers, called the coordinates of that point. Similarly, every place in this world is denoted by a latitude and longitude, which give us the coordinates of that place. Then, we know that the time period is directly proportional to the square root of the length of the pendulum. (ii) If the zero error is +0.005 cm, what is the correct diameter? Zero error = +6 × L.C. 46th division of circular scale coincides with the base line. Thus the actual length of the rod is 1.2 cm plus the length ab (i.e., the length between the 1.2 cm mark on the main scale and 0 mark on vernier scale). Students can refer to these solutions whenever they have … (d) The time period of oscillations of simple pendulum is inversely proportional to the square root of acceleration due to gravity. The least count of vernier callipers is equal to the difference between the values of one main scale division and one vernier scale division. The trigonometric ratios of some special angles, i.e., 0°, 30°, 45°, 60° and 90° follow a pattern and are easy to remember. It is determined by measuring the distance between the zero mark of the main scale and the zero mark of the vernier scale. The main scale is graduated to read up to 1 mm and on vernier scale, the length of 10 divisions is equal to the length of 9 divisions on the main scale. For example, for the scales shown, the least count is 0.01 cm and the 6th division of the vernier scale coincides with a main scale division. A screw gauge is used for measuring diameter of circular objects mostly wires with an accuracy of 0.001 cm. The frequency of oscillation of a seconds’ pendulum is 0.5 s-1. of division of circular head in line with the base line (p) = 27 Circular scale reading = (p) × L.C. 100 divisions in 1 m. To what accuracy can this scale measure? When is a vernier calipers said to be free from zero error?
The zero error is of two kinds. Positive zero error: On bringing the two jaws together, if the zero mark of the vernier scale is on the right of the zero mark of the main scale, the error is said to be positive. No, the pendulum used in pendulum clock is not a simple pendulum because the simple pendulum is an ideal case. 1 quintal = 100 kg 1 metric tonne = 1000 kg, (a) 1 g = 10-3 kg (b) 1 mg = 10-6 kg (c) 1 quintal = 100 kg (d) 1 a.m.u (or u) = 1.66 x 10-27 kg.